2/3x^2-3/2x+1=x^2+x

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Solution for 2/3x^2-3/2x+1=x^2+x equation:



2/3x^2-3/2x+1=x^2+x
We move all terms to the left:
2/3x^2-3/2x+1-(x^2+x)=0
Domain of the equation: 3x^2!=0
x^2!=0/3
x^2!=√0
x!=0
x∈R
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We get rid of parentheses
-x^2+2/3x^2-3/2x-x+1=0
We calculate fractions
We do not support expression: x^3

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